CVPM Capstone

CVPM Capstone

In this experiment, the objective is to find what the velocity of an object must be in order for it to reach any given point. In context, I created a soccer field and placed a cone at one point and the ball at another. In the diagram of the field, you can see that a right triangle can be formed from just the two points. Once the field was formed, I quantified the lengths of the X and Y coordinates, since the ball lies on a flat plane. Since the X position of the cone was -30m and the X position of ball was 50m, the total distance between these two points horizontally was 80m. For Y coordinates, the y-value of the cone was 5m and the y-value of the ball was 2m. Therefore, the total distance between these points vertically is 3m. From these x and y values, I calculated the velocity need by using the slope method of rise over run. 3m over 80m is 3/80(m/s); however, since the cone is located on a negative part of the grid for its X-value, the value of the distance the ball travels is negative. Therefore, instead of 3/80(m/s), the velocity will be negative, giving it a velocity of -3/80(m/s). The velocity doesn’t have to be -3/80(m/s), it just has to be proportional to 3/80m.

By finding the velocity of that the object must travel in order reach a certain point allows you to use any starting point and reach any unknown point wish to reach. When using VPython, the y coordinate isn’t used to measure the vertical shift of the object but rather its height on a 3-D plane. Altering the Z-coordinate is what substitutes for the up and down shift on the plane. However, on a flat plane like the diagram, the Y coordinate is what is used to change the vertical position of an object. Keep this in mind because it becomes very confusing if you don’t understand the correlation between a flat plane on a paper diagram and a 3-D plane on VPython.

In conclusion, from the ball’s starting position of (50,0,2)m, I discovered that the soccer ball’s velocity of -3/80(m/s) successfully arrived me at the position of the cone (-30,0,5)m in approximately 9.8s.

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