The blog network for Mr. Burk's Physics Classes
Using a simple spreasheet, I’ve found how the force of gravity on the balloon changes over time. The gravitational force changes because the balloon moves farther and farther away from the earth. If you look at the formula for Gravitational force, you’ll notice that little R squared on the bottom. This is the distance between the [...]
I am having to stop this capstone early unfortunately. I am afraid I have run out of time. I feel like I have done good work on this just I have stopped short on the fine tuning.
Now I am off to preparing for my Exam!
This is an improvement over your previous work. You’ve done a good job of checking sports science. To be fully complete however, you need to show me how you calculated the various velocities—you can include screenshots from your work with tracker.
Nice work. How different is the gravitational force on the balloon when it is launched vs when it gets to maximum height? Explain this and we’ll say this is complete.
Henry, This is excellent. One thing I’m particularly curious about is how you determined the velocity of the egg. Did you find the velocity right after it fell only using a couple of points, or did you use a bunch of points and find some sort of average velocity? Which do you think would be [...]
Saul, I think first question was unclear. Let me try again. Your experiment is very similar to something like a cannon, mounted to a rail car, launching a cannon ball backward. The initial momentum was zero, and aftwerward, the cannonball and rail car have opposite momenta. Similarly, the fan and coat hanger in your experiment [...]
Angular momentum is the mass of the object times the angular velocity times the radius. Angular velocity would be the rate of change of angular displacement of an object. It could be measured by the fraction of the circumference of the circle that encompasses the distance traveled divided by the time it takes to travel [...]
this is done.
Also, I see that it my my error in my previous comment that said the velocity was 65 m/s. I’m sorry about that. I was typing too fast. The actual maximum velocity in m/s is 29 m/s. Again, I think you should be able to fix your graph with just a few minutes of work.
Sarah, I think you’ve got some physics problems in your analysis/graph you still need to resolve. The maximum velocity of the ride is 65 mi/h, not m/s. This is why the value you got for the distance the ride falls is way too high (225 m is taller than anything in the park). Also, I [...]
Noah, It would be very hard for a reader not familiar with your work to understand at all what you are doing here. Can you add explanations, 1-2 sentences to each calculation so that someone can understand your work? Also, now that you have an impulse, you should estimate a time for the collision (does [...]
Excellent work. This is finished. But I wonder what force is required to break an egg?
Nice work. This is complete. Feel free to test it with the loop in our classroom.
Well someone beat me to it. They solved for the ascent rate. Mad props to them because it would’ve taken me much longer. http://www.wired.com/wiredscience/2012/05/angular-size-and-the-height-of-a-space-balloon/ Now lets see If our data lines up with the data of the launch. The wired article puts the velocities around 3.2 and 4.5 m/s^2. If we make that into a [...]
I think your are basically done. But I think you’ve got a bit of misunderstanding about impulse. You’ve calculated the speed right before it hits the pillow. Now you need to calculate the change in momentum to bring it to rest. This is the impulse that the catcher must provide. You are right that impulse [...]